Yep. That was it. Stupid me...
On Nov 13, 4:10 pm, Michael Bayer <[EMAIL PROTECTED]> wrote:
> On Nov 13, 2007, at 8:25 AM, Koen Bok wrote:
>
> > Hi, I have this strange bug or problem...
>
> > I have a basic class like this mapped to a table with the same name.
> > Metatype is a relation to the metatype object.
>
> > class MetaData(DBObject):
>
> > def __init__(self, metatype, value, item):
>
> > self.metatype = metatype
> > self.item = item
> > self.value = value
>
> > class MetaType(DBObject):
>
> > def __init__(self, name, parent=None, offset=None):
>
> > self.parent = parent
> > self.offset = offset
> > self.name = name
>
> > Now when I create a MetaData object like this I get the following
> > error:
>
> >>>> nameMetaType = MetaType('name')
> >>>> product = Product(Decimal('20.00'), Decimal('15.00'))
> >>>> Session.commit()
>
> >>>> MetaData(nameMetaType, 'Koen', product)
>
> > Traceback (most recent call last):
> > method testMetabug in test_connection.py at line 16
> > MetaData(nameMetaType, 'Koen', product)
> > method init in attributes.py at line 1025
> > oldinit(instance, *args, **kwargs)
> > TypeError: __init__() takes at most 3 arguments (4 given)
>
> what happens if you change the name "MetaData" to something else ?
> your error below seems to indicate that your MetaData class/object is
> getting treated like a SQLAlchemy "MetaData" object.
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