Hi All, I am seeing something I didn't expect using in_.
Here is a simple example, exactly as I expect: In [13]: col = Trade.c.TradeId.in_([1,2]) In [14]: sel = select([col]) In [15]: print col "Trade"."TradeId" IN (?, ?) In [16]: print sel SELECT "Trade"."TradeId" IN (?, ?) AS anon_1 FROM "Trade" But now, if I use a subselect, I see a problem: In [17]: col = Trade.c.TradeId.in_(select([Trade.c.TradeId])) In [18]: sel = select([col]) In [19]: print col "Trade"."TradeId" IN (SELECT "Trade"."TradeId" FROM "Trade") In [20]: print sel SELECT "Trade"."TradeId" IN (SELECT "Trade"."TradeId" FROM "Trade") AS anon_1 FROM "Trade", (SELECT "Trade"."TradeId" AS "TradeId" FROM "Trade") The column definition (col) is as expected, but the select definition (sel) is strange. It selects two things and generates n^2 rows. How can I get the select I expect: SELECT "Trade"."TradeId" IN (SELECT "Trade"."TradeId" FROM "Trade") AS anon_1 FROM "Trade" thanks, James --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
