You seem to have stumbled into the same bug as I have while i fixed the "IN" SQL generation code for oracle to work inside the column list, not just in the where-clause.
I ended up hacking SQLAlchemy/trunk/lib/sqlalchemy/sql/expression.py like this: 2166 <https://projects.freecode.no/internal/projects/browser/div4/div4c/software/SQLAlchemy/trunk/lib/sqlalchemy/sql/expression.py#L2166> *class* _BinaryExpression(ColumnElement): ... 2181 <https://projects.freecode.no/internal/projects/browser/div4/div4c/software/SQLAlchemy/trunk/lib/sqlalchemy/sql/expression.py#L2181> *def* *_get_from_objects*(self, **modifiers): 2182 <https://projects.freecode.no/internal/projects/browser/div4/div4c/software/SQLAlchemy/trunk/lib/sqlalchemy/sql/expression.py#L2182> res = self.left._get_from_objects(**modifiers) 2183 <https://projects.freecode.no/internal/projects/browser/div4/div4c/software/SQLAlchemy/trunk/lib/sqlalchemy/sql/expression.py#L2183> *if* self.operator *is* operators.in_op: *return* res 2184 <https://projects.freecode.no/internal/projects/browser/div4/div4c/software/SQLAlchemy/trunk/lib/sqlalchemy/sql/expression.py#L2184> *return* res + self.right._get_from_objects(**modifiers) That seems to do the trick :) Best regards, Egil casbon wrote: > Hi All, > > I am seeing something I didn't expect using in_. > > Here is a simple example, exactly as I expect: > > > In [13]: col = Trade.c.TradeId.in_([1,2]) > > In [14]: sel = select([col]) > > In [15]: print col > "Trade"."TradeId" IN (?, ?) > > In [16]: print sel > SELECT "Trade"."TradeId" IN (?, ?) AS anon_1 > FROM "Trade" > > > But now, if I use a subselect, I see a problem: > > > > In [17]: col = Trade.c.TradeId.in_(select([Trade.c.TradeId])) > > In [18]: sel = select([col]) > > In [19]: print col > "Trade"."TradeId" IN (SELECT "Trade"."TradeId" > FROM "Trade") > > In [20]: print sel > SELECT "Trade"."TradeId" IN (SELECT "Trade"."TradeId" > FROM "Trade") AS anon_1 > FROM "Trade", (SELECT "Trade"."TradeId" AS "TradeId" > FROM "Trade") > > > The column definition (col) is as expected, but the select definition > (sel) is strange. It selects two things and generates n^2 rows. How > can I get the select I expect: > > SELECT "Trade"."TradeId" IN (SELECT "Trade"."TradeId" > FROM "Trade") AS anon_1 > FROM "Trade" > > thanks, > James > > --~--~---------~--~----~------------~-------~--~----~ > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To post to this group, send email to sqlalchemy@googlegroups.com > To unsubscribe from this group, send email to [EMAIL PROTECTED] > For more options, visit this group at > http://groups.google.com/group/sqlalchemy?hl=en > -~----------~----~----~----~------~----~------~--~--- > >
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