thanks a lot for your solution. But i have been caught by the following error. Please help me. bye
(OperationalError) (1054, "Unknown column 'journals.id' in 'on clause'") u'SELECT anon_1.journals_id AS anon_1_journals_id, anon_1.journals_amount AS anon_1_journals_amount, anon_1.journals_entry_date AS anon_1_journals_entry_date, anon_1.journals_type AS anon_1_journals_type, anon_1.journals_party_id AS anon_1_journals_party_id, anon_1.`journals_party_role_ id` AS `anon_1_journals_party_role_ id` \nFROM (SELECT journals.id AS journals_id, journals.amount AS journals_amount, journals.entry_date AS journals_entry_date, journals.type AS journals_type, journals.party_id AS journals_party_id, journals.`party_role_ id` AS `journals_party_role_ id` \nFROM journals \n LIMIT 2, 6) AS anon_1 INNER JOIN ledgers ON journals.id = ledgers.journal_id' [] On Oct 23, 7:03 am, Michael Bayer <[EMAIL PROTECTED]> wrote: > On Oct 23, 2008, at 8:58 AM, ershadul.hoque wrote: > > > > > > > journals table has id column > > ledgers table has journal_id column > > > consider that: journals table is mapped in > > Class Journal(object): > > pass > > and similarly ledgers as : > > Class Ledger(object): > > pass > > > Now i want to run this query ( it runs successfully in mysql): > > > select * from (select * from journals limit 2,6) as some_journal inner > > join ledgers > > on some_journal.id = ledgers.journal_id > > > please help me. > > sess.query(Journal).limit(6).offset(2).from_self().join((Ledger, > Journal.id==Ledger.journal_id)) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
