On Jan 7, 2009, at 11:49 AM, ml wrote:
> > Hi! > > I have 2 tables: > > sortiment(id, ...) <---- translations(id, id_sortiment, language, > text) > > The query > > query > (Sortiment > ).outerjoin(Sortiment.translations).filter(Translation.language="en") > > will never return sortiment item with missing "en" translation because > the filter (useless outerjoin). I need the Translation.language="en" > embed into the outerjoin but the language must be variable. This is a > general problem of creating variable joins on session queries. > Is there any simple way? > you'd filter on or_(Translation.language=="en", Translation.language==None) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
