On Feb 10, 2010, at 2:49 PM, Kent wrote: > After merge() returns, is there a way for me to pair each object in > the returned merge_obj with the object it was created from? > > For example: > merged_obj = session.merge(object) > > At the top level, it is trivial, merged_obj was created because of the > instance "object" > > For single RelationProperties under the top level, it is fairly > simple, too. > > That is: > > merged.childattr was merged from object.childattr > > Where it falls apart I think is if the RelationProperty.use_list == > True > > merged.list came from object.list, but is there a way for me to > reference the original objects inside the list. > > Did merged.list[0] come from object.list[0] or object.list[1] or > object_list[2]? > > I particularly can't use the pk because it won't always be set (often > this will be a new record) > > Any suggestions?
the ordering of those lists (assuming they are lists and not sets) are deterministic, especially with regards to the pending objects that have been added as a result of your merge (i.e. the ones that wont have complete primary keys). I would match them up based on comparison of the list of instances that are transient/pending. > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To post to this group, send email to sqlalch...@googlegroups.com. > To unsubscribe from this group, send email to > sqlalchemy+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/sqlalchemy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalch...@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
