On Sep 2, 2010, at 6:51 PM, cd34 wrote: > meta.Session.query(Job).order_by(Job.min_level).order_by(Job.descr).filter(Job.tier==1).outerjoin((User_job_progress, > User_job_progress.job_id==Job.job_id)).filter(User_job_progress.fb_uid==1) > > results in a query of: > > FROM xxx_jobs LEFT OUTER JOIN xxx_user_job_progress ON > xxx_user_job_progress.job_id = xxx_jobs.job_id > WHERE xxx_jobs.tier = %s AND xxx_user_job_progress.fb_uid = %s ORDER > BY xxx_jobs.min_level, xxx_jobs.descr > > but, what I am trying to achieve is > > FROM xxx_jobs LEFT OUTER JOIN xxx_user_job_progress ON > (xxx_user_job_progress.job_id = xxx_jobs.job_id > AND xxx_user_job_progress.fb_uid = %s) WHERE xxx_jobs.tier = %s ORDER > BY xxx_jobs.min_level, xxx_jobs.descr > > I tried putting the .filter within the outerjoin, but the tuple object > has no attribute filter. Adding a second condition results in > ValueError: too many values to unpack. Passing a list doesn't appear > to be parsed as there is no attribute _from_objects.
you need to use and_(), and pass the criterion as a list inside, from sqlalchemy import and_ query.outerjoin((target, and_(foo.bar==q, bar.bat==x)) -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalch...@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
