from sqlalchemy import func, distinct query(Invoice.user_name, func.count(distinct(Item.id))).join(Invoice.items).group_by(Invoice.user_name)
On Jan 20, 2011, at 9:51 AM, NiL wrote: > Hi Michael, > > thank you very much for your prompt answer. > > What I want to achieve is, counting the number of distinct items, > grouped by user_name > > Given > > Item1: > item_id = 1 > service_id = 'test' > item_class = 'dummy' > Item2: > item_id = 2 > service_id = 'other' > item_class = 'dummy' > > Invoice1: > id = 1 > user_name = 'lorem' > item = Item1 > Invoice2: > id = 2 > user_name = 'lorem' > item = Item1 > Invoice3: > id = 3 > user_name = 'ipsum' > item = Item1 > Invoice4: > id = 4 > user_name = 'ipsum' > item = Item2 > > the expected result is: > > user: lorem, distinct item count : 1 > user: ipsum, distinct item count : 2 > > > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To post to this group, send email to sqlalchemy@googlegroups.com. > To unsubscribe from this group, send email to > sqlalchemy+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/sqlalchemy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
