session.query(Invoice.user_name, Item).join(Invoice.item).distinct().from_self(Invoice.user_name, func.count(1)).group_by(Invoice.user_name)
On Jan 20, 2011, at 11:45 AM, NiL wrote: > thanks again > > but the unicity of Item is guaranteed by the triplet of PK > > I can't just discriminate the distinct() based on the item_id only (it > is not unique by itself in my set of data) > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To post to this group, send email to sqlalchemy@googlegroups.com. > To unsubscribe from this group, send email to > sqlalchemy+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/sqlalchemy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
