To put it more clear why:
rows = session.query(*[func.count().over().label("count")]+map(lambda column:
MyClass.__dict__[columns],columns)).filter(...).limit(n).offset(m).all()
works and
*rows = session.query(*[func.count().*
*over().label("count")]+map(**lambda column:
MyClass.__dict__[columns],**columns)).filter(...).distinct().limit(n)**.offset(m).all()*
does not?
Thanks
Am Mittwoch, 16. Mai 2012 12:07:26 UTC+2 schrieb Eduardo:
>
> Hello,
> I have got a query of the following type:
>
> rows = session.query(*[func.count().over().label("count")]+map(lambda column:
> MyClass.__dict__[columns],columns)).filter(...).limit(n).offset(m).all()
>
> it returns the number of results together with values of selected columns.
> The problem is when I try to apply the distinct query I see that
> func.count().over().label("count") does not return correct results, that is,
> it returns the number of results for the query by which the distinct function
> is omitted.
> Is there any workaround for this problem?
> The query contains no joins.
> Thank you
> ED
>
>
--
You received this message because you are subscribed to the Google Groups
"sqlalchemy" group.
To view this discussion on the web visit
https://groups.google.com/d/msg/sqlalchemy/-/W80zRGtGptAJ.
To post to this group, send email to sqlalchemy@googlegroups.com.
To unsubscribe from this group, send email to
sqlalchemy+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/sqlalchemy?hl=en.
