Hi I'm facing another column_expression issue. It is not related to the previous issue, and I'm sure if SQLAlchemy can help me with this one.
---- from sqlalchemy.types import UserDefinedType from sqlalchemy.sql import func class Geometry(UserDefinedType): def column_expression(self, col): return func.ST_AsBinary(col, type_=self) from sqlalchemy import Table, Column, MetaData lakes = Table('lake', MetaData(), Column('geom', Geometry) ) from sqlalchemy.sql.expression import select, alias s = select([lakes]) a = alias(s, 'name') s = a.select() print s ---- The print statement returns this: SELECT ST_AsBinary(name.geom) AS geom FROM (SELECT ST_AsBinary(lake.geom) AS geom FROM lake) AS name Which is expected. But the execution of this statement fails in my PostGIS database, because ST_AsBinary cannot receive a bytea value as input. (the outer ST_AsBinary call receives what's returned from the inner ST_AsBinary call). It would work if ST_AsBinary was idempotent, but it's not in PostGIS 2 (<http://trac.osgeo.org/postgis/ticket/1869>). I'm stuck on this one. -- Eric Lemoine Camptocamp France SAS Savoie Technolac, BP 352 73377 Le Bourget du Lac, Cedex Tel : 00 33 4 79 44 44 96 Mail : eric.lemo...@camptocamp.com http://www.camptocamp.com -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.