printing a SQL construct invokes the default dialect which doesn't support 
Postgresql operators, use compile() for stringification:

from sqlalchemy.dialects import postgresql
dialect = postgresql.dialect()

print stmt.compile(dialect=dialect)


On May 28, 2013, at 10:23 AM, Jon Nelson <jnel...@jamponi.net> wrote:

> I'm having difficulty using PostgreSQL's ANY operator (for use with arrays).
> I've tried several variations of the syntax provided in the
> documentation, but all I ever get is:
> 
> AttributeError: 'SQLCompiler' object has no attribute 'visit_any'
> 
> What am I likely doing wrong?
> I've tried (using declarative-derived mappers):
> 
> print sess.query(ObjectA, dialects.postgresql.Any(ObjectA.column1,
> ObjectB.column1))
> and
> print dialects.postgresql.Any(ObjectA.column1, ObjectB.column1)
> and
> print ObjectB.column1.any(ObjectA.column1)
> 
> I am declaring ObjectB.column1 as an ARRAY(Integer()) and
> ObjectA.column1 is an Integer().
> 
> 
> --
> Jon
> Software Blacksmith
> 
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