Hey guys, Questions about the following code in which I'm trying to take a textqual query and join it to a query builder query.
1) What is the correct way to do the in for the list of ids in the first query? My current way doesn't work and I'm not able to find a real good example 2) How can I Join complicated query 2 with complicated query 1. Essentially join query 2 on sm.StufffModel.id == query1.id Complicated query 1: image_res = db.session.query("id", "depth", "parent_id", "name", "s3_key").from_statement( """ WITH RECURSIVE graph(root_id, id, name, parent_id) AS ( SELECT e.id, e.id, e.name, e.parent_id, 1 as depth FROM entities e UNION ALL SELECT graph.root_id, e.id, e.name, e.parent_id, depth + 1 FROM graph JOIN entities e ON e.parent_id=graph.id ) SELECT g.id,g.depth, g.parent_id, name, ii.s3_key FROM graph g JOIN entity_map em ON g.id=em.left_id JOIN stufff_images si ON em.right_id=si.id JOIN image_instance ii ON si.image_id=ii.image_id WHERE root_id in (:ids) AND ii.width=120 ORDER BY depth ASC LIMIT 1; """).params(ids=",".join([str(i) for i in ids]))) Complicated query 2: query = db.session.query( sm.StufffModel.id, sm.EntityTypesModel.type, sm.StufffModel.hotness, sm.StufffModel.created_at, sm.StufffModel.name) query = query.join(sm.EntityTypesModel) query = query.filter(sm.StufffModel.id.in_(ids)) res = query.all() Thanks, Amir -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/groups/opt_out.