Thanks Mike, the assurance it's the right idea was what I wanted to check.

All sorted much appreciated.

On Sun, 7 Feb 2021, 21:49 Mike Bayer, <mike...@zzzcomputing.com> wrote:

>
>
> On Sat, Feb 6, 2021, at 8:56 AM, Chris Simpson wrote:
>
> After posting, I have arrived at *a* solution (which might be awful)
> Please let me know if this is a bad approach or I'm following the api
> correctly:
>
> I have converted this SQL query:
>
> SELECT COUNT(*)
> FROM person
> JOIN subscription ON
> person.id = subscription.person_id
> JOIN plan ON
> subscription.sku_uuid = plan.uuid
> JOIN plan_requirements ON
> plan.id = plan_requirements.plan_id
> WHERE plan_requirements.subscription = 1
>
> Into the following SQLAlchemy query:
>
> database.session.query(Person)\
> .join(Subscription)\
> .join(Plan, Subscription.sku_uuid==Plan.uuid)\
> .join(PlanRequirements, Plan.id==PlanRequirements.plan_id)\
> .filter(PlanRequirements.subscription==1).all()
>
>
> seems to be the right idea except you aren't emitting the "COUNT(*)" part
> of it, not sure if that's what you wanted.
>
>
> Kind regards,
>
> Chris
> On Saturday, 6 February 2021 at 13:42:54 UTC Chris Simpson wrote:
>
> Hello,
>
> I'm trying to convert this working SQL query: (SQLAlchemy models are below)
>
> SELECT COUNT(*)
> FROM person
> JOIN subscription ON
> person.id = subscription.person_id
> JOIN plan ON
> subscription.sku_uuid = plan.uuid
> JOIN plan_requirements ON
> plan.id = plan_requirements.plan_id
> WHERE plan_requirements.subscription = 1
>
> Into a SQLAlchemy query. so far from reading the docs
> <https://docs.sqlalchemy.org/en/13/orm/tutorial.html>,  I have the
> following:
>
> database.session.query(Person).join(Subscription).filter(Subscription.plan.has()
> ).all()
>
> With the objective: Show me all people who have at least one plan with the
> plan_requirements.subscription set to 1 (meaning true).
>
> Do I need to somehow keep chaining my joins?
>
> My SQLAlchemy Models are: (full code is also linked at end)
>
> class Person(database.Model):
>     __tablename__ = "person"
>     id = database.Column(database.Integer(), primary_key=True)
>     uuid = database.Column(database.String(), default=uuid_string)
>     given_name = database.Column(database.String())
>     family_name = database.Column(database.String())
>     subscriptions = relationship("Subscription", back_populates="person")
>
> class Plan(database.Model):
>     __tablename__ = "plan"
>     id = database.Column(database.Integer(), primary_key=True)
>     uuid = database.Column(database.String(), default=uuid_string)
>     requirements = relationship(
>         "PlanRequirements", uselist=False, back_populates="plan"
>     )
>
>
> class PlanRequirements(database.Model):
>     __tablename__ = "plan_requirements"
>     id = database.Column(database.Integer(), primary_key=True)
>     plan_id = database.Column(database.Integer(), ForeignKey("plan.id"))
>     plan = relationship("Plan", back_populates="requirements")
>     instant_payment = database.Column(database.Boolean(), default=False)
>     subscription = database.Column(database.Boolean(), default=False)
>
> Full source code of models:
> https://github.com/Subscribie/subscribie/blob/master/subscribie/models.py#L40
> <https://github.com/Subscribie/subscribie/blob/master/subscribie/models.py#L40>
>
> Much appreciated if someone can point me in the right directly. I'm
> confident with the SQL quiery, just not how to convert that to the ORM.
>
>
> --
> SQLAlchemy -
> The Python SQL Toolkit and Object Relational Mapper
>
> http://www.sqlalchemy.org/
>
> To post example code, please provide an MCVE: Minimal, Complete, and
> Verifiable Example. See http://stackoverflow.com/help/mcve for a full
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>
>
> --
> SQLAlchemy -
> The Python SQL Toolkit and Object Relational Mapper
>
> http://www.sqlalchemy.org/
>
> To post example code, please provide an MCVE: Minimal, Complete, and
> Verifiable Example. See http://stackoverflow.com/help/mcve for a full
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-- 
SQLAlchemy - 
The Python SQL Toolkit and Object Relational Mapper

http://www.sqlalchemy.org/

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