class Objekt(db.Model):
__tablename__ = 'objekt'
def __init__(self,**kwargs):
super().__init__(**kwargs)
id = db.Column(db.Integer, primary_key=True)
typ_id = db.Column(db.Integer, db.ForeignKey('objekt_typ.id'))
typ = db.relationship("ObjektTyp")
name = db.Column(db.String(100))
__mapper_args__ = {
'polymorphic_on': typ_id
}
class ChildObjekt1(Objekt):
__versioned__ = {}
__tablename__ = 'child_objekt1'
@staticmethod
def TypId():
return 7
# User fields
def __init__(self,**kwargs):
super().__init__(**kwargs)
#super().__init__(typ_id=ChildObjekt1.TypId(), **kwargs)
###
id db.Column(db.Integer, db.ForeignKey('objekt.id'),
primary_key=True)
text = db.Column(db.String(255 ), default='')
__mapper_args__ = {
'polymorphic_identity': 7,
}
leads to:
venv\lib\site-packages\sqlalchemy\orm\mapper.py", line 1542, in
_configure_polymorphic_setter
self.polymorphic_on = self._props[self.polymorphic_on]
KeyError: 'typ_id'
raise exception
sqlalchemy.exc.ArgumentError: Can't determine polymorphic_on value
'typ_id' - no attribute is mapped to this name.
maybe i do something totally worg.. I am also using sql continuum
------ Originalnachricht ------
Von: "Simon King" <si...@simonking.org.uk>
An: sqlalchemy@googlegroups.com
Gesendet: 12.04.2021 19:06:11
Betreff: Re: [sqlalchemy] Invertinace mapped type_id to fix value for
each child class
I don't understand this comment:
I though on polymorphic_on, but I think that does not work because of the fact
that type_id ha a foreign key ...
As far as I can tell, you ought to have this in the base class:
__mapper_args__ = {
'polymorphic_on': typ_id
}
And this in the subclass:
__mapper_args__ = {
'polymorphic_identity': 7,
}
...and you should get rid of the typ_id function and the
"Objekt.typ_id = ChildClass.typ_id" line.
Does that work for you?
Simon
On Mon, Apr 12, 2021 at 5:18 PM 'Sören Textor' via sqlalchemy
<sqlalchemy@googlegroups.com> wrote:
I run into a problem and don't know how to solve it.
The theory is very simple: I habe one base class table with name, id and type
column
The child class shall have a unique type_id (all child_class1 objekt shall get
type_id 7, all child_class2 objekts type_id = 8, ...)
How can I map the base class typ_id to an hard coded value for eahc class type.
My actual approach does not change the type_id-columns of Objekt and after
saving the objekt the column Objekt.type_id entry is always empty for all
entries :-(
class Objekt(db.Model):
__tablename__ = 'objekt'
def __init__(self,**kwargs):
super().__init__(**kwargs)
id = db.Column(db.Integer, primary_key=True)
typ_id = db.Column(db.Integer, db.ForeignKey('objekt_typ.id'))
typ = db.relationship("ObjektTyp")
name = db.Column(db.String(100))
class ChildClass1(Objekt):
__tablename__ = 'child_class1'
@staticmethod
def typ_id():
return 7
def __init__(self,**kwargs):
super().__init__(**kwargs)
Objekt.typ_id = ChildClass1.typ_id() ### fix type
id = db.Column(db.Integer, db.ForeignKey('objekt.id'), primary_key=True)
text = db.Column(db.String(255 ), default='')
__mapper_args__ = {
'polymorphic_identity':'child_class1',
}
any ideas where to look? I though on polymorphic_on, but I think that does not
work because of the fact that type_id ha a foreign key ...
SirAnn
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http://www.sqlalchemy.org/
To post example code, please provide an MCVE: Minimal, Complete, and Verifiable
Example. See http://stackoverflow.com/help/mcve for a full description.
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