P Kishor wrote:

> 
> try
> 
> SELECT * FROM dictionary WHERE Word = '"eleven"';

<snip>

>>  I am sure this is due to the fact that I am an idiot, but I could use
>>  some help.
>>

<snip>

It worked.

I was correct. I am an idiot.

Thank you for the help. Lesson learned.

George

---
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