2009/12/3 Yuzem <naujnit...@gmail.com>: > > Thanks both for the replies. . . . . > SimonDavies wrote: >> >> SELECT a.id,a.title,a.rating,tag.tag FROM (movies natural left join >> user) as a natural left join tag; >> > It doesn't work, it says: no such column a.id > If I use movies.id I have the same problem as before: movies with no rating > don't get any tags. >
This is what I see: C:\>sqlite3 yuzem.db SQLite version 3.4.2 Enter ".help" for instructions sqlite> sqlite> sqlite> create table movies( id integer primary key, title text ); sqlite> insert into movies( title ) values( 'movie1' ); sqlite> insert into movies( title ) values( 'movie2' ); sqlite> insert into movies( title ) values( 'movie3' ); sqlite> sqlite> create table user( id integer primary key, rating text ); sqlite> insert into user( rating ) values( 'rating1' ); sqlite> insert into user( rating ) values( 'rating2' ); sqlite> sqlite> create table tag( id integer primary key, tag text ); sqlite> insert into tag( tag ) values( 'tag1' ); sqlite> insert into tag( tag ) values( 'tag2' ); sqlite> insert into tag( tag ) values( 'tag3' ); sqlite> sqlite> SELECT a.id,a.title,a.rating,tag.tag FROM (movies natural left join user ) as a natural left join tag; 1|movie1|rating1|tag1 2|movie2|rating2|tag2 3|movie3||tag3 sqlite> Regards, Simon _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
