I have to migrate from MySQL to SQLite3. Following query in mysql gives the Rank for each employee within his dept on the basis of salary.
mysql-> select e.DEPTNO, e.EMPNO, e.LASTNAME, e.FIRSTNAME, e.SAL, find_in_set(e.SAL, x.SALLIST) RANK -> from EMPLOYEES as e, (select DEPTNO, group_concat(SAL order by SAL desc) SALLIST -> from EMPLOYEES -> group by DEPTNO) as x -> where e.DEPTNO = x.DEPTNO -> order by DEPTNO, RANK; I have used following query but it takes more than one hour even after indexing, mysql->select a.DEPTNO, a.EMPNO, a.LASTNAME, a.FIRSTNAME, a.SAL, -> (select 1 + count(*) -> from EMPLOYEES b -> where b.DEPTNO = a.DEPTNO -> and b.SAL > a.SAL) RANK -> from EMPLOYEES as a -> order by x.DEPTNO, x.RANK; My questions are 1. How to find Rank in SQLite? 2. group_concat does not have order by clause, My data is already sorted, but would output of group_concat be unsorted? 3. How to implement find_in_set in SQLite? Please note that my database contains more than two lakhs rows. Regards, shahj Disclaimer note on content of this message including enclosure(s)and attachments(s): The contents of this e-mail are the privileged and confidential material of National Stock Exchange of India Limited (NSE). The information is solely intended for the individual/entity it is addressed to. If you are not the intended recipient of this message, please be aware that you are not authorized in any which way whatsoever to read, forward, print, retain, copy or disseminate this message or any part of it. If you have received this e-mail in error, we would request you to please notify the sender immediately by return e-mail and delete it from your computer. This e-mail message including attachment(s), if any, is believed to be free of any virus and NSE is not responsible for any loss or damage arising in any way from its use. _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users