At 16:45 17/04/2007, Stef Mientki wrote:
I don't understand this behaviour,
is this too complex ?
or am I doing something wrong ?
I use the following syntax, and I get 7 records back,
(which is not correct in my opinion)
SELECT PO.* FROM Koppel
LEFT JOIN PO
WHERE (Koppel.K_App == PO.App)
AND (Koppel.K_naam == 'MVE')
AND (PO.ALL_answered == '0')
SELECT PO.* FROM Koppel
LEFT JOIN PO
WHERE (Koppel.K_App == PO.App)
AND (Koppel.K_naam == 'MVE')
AND (PO.ALL_answered != '0')
I don't know if this is the problem, but, for some reason you're
mixing C/C++ syntax in with SQL there.
You don't use '==', you should just use '='
You don't use '!=', you should use '<>'
So, try
SELECT PO.* FROM Koppel
LEFT JOIN PO
WHERE (Koppel.K_App = PO.App)
AND (Koppel.K_naam = 'MVE')
AND (PO.ALL_answered <> '0')
Paul VPOP3 - Internet Email Server/Gateway
[EMAIL PROTECTED] http://www.pscs.co.uk/
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