Jan Kara <[email protected]> writes: > On Thu 14-07-11 12:30:32, Jeff Moyer wrote: >> Tao Ma <[email protected]> writes: >> >> - WRITE_SYNC_PLUG will plug the queue and expects explicity unplug. Who >> >> is doing unplug in this case? >> > See the comments I removed, "we rely on sync_buffer() doing the unplug >> > for us". I removed them cause we all use pluged write now. >> >> Your logic is upside-down. The code currently only uses the _PLUG >> variant when t_synchronous_commit is set, meaning somebody *will* call >> sync_buffer. Simply setting WRITE_SYNC_PLUG doens't mean the upper >> layer is going to issue the unplug. Of course, I'm not 100% sure of the >> journaling process, so it may very well be that there always is an >> unplug. Can Jan or someone comment on that? Anyway, you could test >> this theory by seeing if your kernel generates any timer unplugs in the >> blktrace output. > So I'm not expert in plugging code but from what I understand when we do > wait_on_buffer() (which calls io_schedule()) which will do > blk_flush_plug()), the queue will get unplugged and IO starts. And we wait > for all buffers we submit so we are guaranteed wait_on_buffer() will be > called...
Sorry, I should have been more specific. As Vivek mentioned, we're talking about older kernels (pre the blk plugging series). So, the question is, if journal_commit_transaction is called with t_synchronous_commit not set, will the underlying device ever be unplugged by the journal code? My guess is there's no explicit unplug, so it's not correct to replace a WRITE_SYNC with a WRITE_SYNC_PLUG. Cheers, Jeff _______________________________________________ stable mailing list [email protected] http://linux.kernel.org/mailman/listinfo/stable
