Don't you hate it when you publish numbers with errors....
I manually subtracted from noon incorrectly
3) The time difference to noon is actually 2h 47m 31s
Multiply by 15 gives 41d 52m 45s E
Open a new clock and enter the longitude, and equator
The result is near a town called Chisimayu in Somalia, near the Kenya
border, where the sun will be overhead at solar noon, at the equinox
On 2011-09-23 2:12, David Patte wrote:
Also using Time Zone Master
1) Clicking any clock and going to the equinox page, you then click on
the equinox (5:05 EDT for my case - Ottawa)
2) Then go to the sidereal page it shows 9:12:28 GST (sidereal time)
3) The time difference to noon is 2h 57m 31s
Multiply x 15 - you get 44d 22m 45s E
It shows a delta-T of 67 seconds
On 2011-09-22 23:59, James E. Morrison wrote:
My logic for answering the question of where on Earth will it be
apparent noon at the instant of the autumnal equinox is:
1. The Greenwich sidereal time at the time of the equinox (Julian
day 2455827.87793) is 09:10:36.1
2. We want the longitude where the local sidereal time = 12:00:00 at
this instant.
3. The sidereal time difference is 02:49:24.
4. Times 15 for degrees = 42d 20m 59s E.
This corresponds to a meridian passing through Georgia, east Turkey
and bit west of Baghdad.
I used The Electric Astrolabe with a Delta-T of 66 sec to get the GST
value. Other programs may improve on the result.
Best regards,
Jim
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