Hi,
On Mon, Feb 08, J-L Boers wrote:
> / PPS: Want some challenge? Find the formula that gives you a torus ;-)
>
> It's pretty neat.The flat torus formula:
>
> [u,v] -> [cos(u + v), sin(u + v), cos(u - v), sin(u - v)]/sqrt(2)
>
> where u and v both run from zero to 2 pi. The sum of the squares of these
> four coordinates is 1 so the object is completely contained in the
> hypersphere of radius 1 centered at the origin in four-space.
Cute ;)
But that's too easy. The question was meant to be: Find an equation
f(x,y,z)=0 so that all solutions of the equation form the surface of a
torus. To be honest: I don't know the solution. I even don't know if this
equation exists ;)
-o)
Hubert Mantel Goodbye, dots... /\\
_\_v
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