As I recall it, there is no overlap between operator characters and identifier characters. If it's not in the operator set, it's effectively reserved for identifiers.
I also remember someone from Apple confirming what Brent said but I can't find it at the moment. Félix > Le 3 janv. 2016 à 03:47:39, Developer via swift-evolution > <swift-evolution@swift.org> a écrit : > > Well, that's just it. $ is a perfectly valid character in identifiers > everywhere but in the grammar for operators for some reason. It isn't > reserved, it just isn't there. > > ~Robert Widmann > > 2016/01/03 0:53、Brent Royal-Gordon <br...@architechies.com> のメッセージ: > >>> Swift currently does not allow operators to use $ - I assume because the >>> grammar reserves it in one place: `implicit-parameter-name`. I don't see >>> why an entire class of identifiers has been eliminated, so I propose $ >>> instead be reclassified as an `operator-character` so it can be used mixed >>> in with other such characters, but prevents the introduction of >>> `$Identifier`-style declarations that might conflict with implicit >>> parameters. >> >> I believe the reason you don't see any other $ variables is that they're >> reserved for the debugger and REPL. >> >> brent@Brents-MacBook-Pro ~/D/Code> swift >> Welcome to Apple Swift version 2.1.1 (swiftlang-700.1.101.15 >> clang-700.1.81). Type :help for assistance. >> 1> "foo" >> $R0: String = "foo" >> 2> print($R0) >> foo >> >> -- >> Brent Royal-Gordon >> Architechies >> > _______________________________________________ > swift-evolution mailing list > swift-evolution@swift.org > https://lists.swift.org/mailman/listinfo/swift-evolution _______________________________________________ swift-evolution mailing list swift-evolution@swift.org https://lists.swift.org/mailman/listinfo/swift-evolution
