Is it considered infeasible for any characters to be allowed in both identifiers and operators?
On Sun, Jan 3, 2016 at 1:23 PM, Chris Lattner via swift-evolution < swift-evolution@swift.org> wrote: > > > On Jan 2, 2016, at 11:53 PM, Brent Royal-Gordon via swift-evolution < > swift-evolution@swift.org> wrote: > > > >> Swift currently does not allow operators to use $ - I assume because > the grammar reserves it in one place: `implicit-parameter-name`. I don't > see why an entire class of identifiers has been eliminated, so I propose $ > instead be reclassified as an `operator-character` so it can be used mixed > in with other such characters, but prevents the introduction of > `$Identifier`-style declarations that might conflict with implicit > parameters. > > > > I believe the reason you don't see any other $ variables is that they're > reserved for the debugger and REPL. > > > > brent@Brents-MacBook-Pro ~/D/Code> swift > > Welcome to Apple Swift version 2.1.1 (swiftlang-700.1.101.15 > clang-700.1.81). Type :help for assistance. > > 1> "foo" > > $R0: String = "foo" > > 2> print($R0) > > foo > > Right. That said, our current operator space (particularly the unicode > segments covered) is not super well considered. It would be great for > someone to take a more systematic pass over them to rationalize things. > > -Chris > _______________________________________________ > swift-evolution mailing list > swift-evolution@swift.org > https://lists.swift.org/mailman/listinfo/swift-evolution >
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