> Am 11.06.2016 um 14:23 schrieb Brent Royal-Gordon <br...@architechies.com>:
>
>> The only magic would be that all type definitions (`protocol` etc.) which do
>> not give a supertype they conform to, will implicitly conform to `Any`, i.e.
>>
>> protocol Foo { … }
>>
>> means
>>
>> protocol Foo : Any { … }
>
> Any is also the supertype of all structural types, and structural types
> cannot conform to protocols.
AFAIK Swift does not support structural types and I am not sure whether we
should change that. In that case `Any` would become magic, yes.
-Thorsten
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