I’m aware what a label is, I just had a small misunderstanding about nested destructuring. ;-)
Issue solved for me. let (a, b /* inner tuple */) = tuple let (_, (x, y)) = tuple +1 I don’t mind this change at all. -- Adrian Zubarev Sent with Airmail Am 5. Mai 2017 um 08:14:10, Xiaodi Wu (xiaodi...@gmail.com) schrieb: On Fri, May 5, 2017 at 1:12 AM, Adrian Zubarev <adrian.zuba...@devandartist.com> wrote: Oh pardon, on the first glance I didn’t realized the issue with that example. Here is an updated example that would work: let (first, second: (x, y)): (first: Int, second: (x: Int, y: Int)) = tuple This should work right? No, again, this would be banned. You are using a label (a thing that ends in a colon) inside a tuple pattern (a thing between parenthesis that comes after "let"). It’s assigning the inner tuple to second while also creating two additional constants from the inner tuple. I know this is redundant and can be used as second.x, but this should work like right, because it’s nested tuple destructuring? If we’d use var instead of let then x would contain the value assigned from the inner tuple, but it would be completely independent from the new second tuple variable. -- Adrian Zubarev Sent with Airmail Am 5. Mai 2017 um 08:04:07, Xiaodi Wu (xiaodi...@gmail.com) schrieb: let (first: a, second: (x: b, y: c)): (first: Int, second: (x: Int, y: Int)) = tuple // fine, unaffected This would be banned. You are using labels (things ending with a colon) in a pattern (the stuff that comes after the word "let").
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