Not answering the questions, but sharing a neat trick.
[weak self] in
guard let `self` = self else { return }
self.foo() // strong self :)
--
Adrian Zubarev
Sent with Airmail
Am 1. Mai 2017 um 16:46:33, Rien via swift-users ([email protected])
schrieb:
In my code I use a lot of queues. And (very often) I will use [weak self] to
prevent doing things when ‘self’ is no longer available.
Now I am wondering: how does the compiler know that [weak self] is referenced?
I am assuming it keeps a reverse reference from self to the [weak self] in
order to ‘nil’ the [weak self] when self is nilled.
But when a job is executing it has no control over the exclusive rights to
[weak self].
I.e. [weak self] may be nilled by an outside event in the middle of say:
if self != nil { return self!.myparam }
The if finding [weak self] non nil, but the return finding [weak self] as nil
Is that correct? i.e. should we never use the above if construct but always:
return self?.myparam ?? 42
Regards,
Rien
Site: http://balancingrock.nl
Blog: http://swiftrien.blogspot.com
Github: http://github.com/Balancingrock
Project: http://swiftfire.nl - A server for websites build in Swift
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