Hello all, I am using Symfony 1.2.2 with doctrine plugin and jQuery. I have created a form in Symfony, which has some filter fields and a submit button. On pressing the submit button my results are being displayed in a new page, but I want to display them below the filter fields using AJAX. How can I capture the click event of submit button of the form? and what should I put in the argument for form_tag ( $action ) ????
Thanks and Regards Vikram --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "symfony users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -~----------~----~----~----~------~----~------~--~---
