Ok. I got it I have to use a form_remote_tag for this task. :) Vikram
On Feb 25, 6:30 pm, SeeVik <[email protected]> wrote: > Hello all, > > I am using Symfony 1.2.2 with doctrine plugin and jQuery. I have > created a form in Symfony, which has some filter fields and a submit > button. On pressing the submit button my results are being displayed > in a new page, but I want to display them below the filter fields > using AJAX. How can I capture the click event of submit button of the > form? and what should I put in the argument for form_tag > ( $action ) ???? > > Thanks and Regards > Vikram --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "symfony users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -~----------~----~----~----~------~----~------~--~---
