Hi,
To display the template in one frame I have following line of code:
<frame src="<?php echo $sf_content ?>"/>
But while accessing the page following error occurs:
Action "StackWorkorder/h1NewStackworkorder" does not exist.
My layout.php code is given below:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
<html xmlns="http://www.w3.org/1999/xhtml"; xml:lang="en" lang="en">
<head>
<?php include_http_metas() ?>
<?php include_metas() ?>
<?php include_title() ?>
<link rel="shortcut icon" href="/favicon.ico" />
<?php include_stylesheets() ?>
<?php include_javascripts() ?>
</head>
<frameset cols="20%,80%">
<frame src="files\leftnav.html"/>
<frame src="<?php echo $sf_content ?>"/>
</frameset>
</html>
Can anybody tell me what I am doing wrong here ?
Thanks,
Sameer B.
-----Original Message-----
From: symfony-users@googlegroups.com [mailto:symfony-us...@googlegroups.com]
On Behalf Of Gábor Fási
Sent: Friday, February 26, 2010 12:09 PM
To: symfony-users@googlegroups.com
Subject: Re: [symfony-users] How to use framset with symfony?
There is no reason why it should not work - it should. Double-check
that you echoed the correct urls in your layout.
On Thu, Feb 25, 2010 at 12:02, SameerB <sameerbhav...@gmail.com> wrote:
> Hi All,
> I am creating an application containing 5 pages and I want to
> show some links at the left side for navigation. I tried adding
> framset in layout.php but it gives "Action does not exits" error
> message. Can anyone tell me or give me some example how to use
> frameset in symfony. Or if it is not supported/possible, what can use
> to display links at the left side which is common to all pages and
> hence should be included in layout.
>
> Thanks in advance,
> SameerB
>
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