Yeah ... is possible to do it automatically. Check sfDoctrineGuardExtraPlugin
On Sun, May 2, 2010 at 9:31 PM, nazgul17 <nazgu...@gmail.com> wrote: > Hello to everyone. I am new to Symfony, so I ask you to forgive me if > my question is a noob question. Anyway, looking in documentation / > tutorials I couldn't find a solution. > > The problem is the following: > I want to build a website where I have only a few pages free to view > for every one. Those who wants to see all the other page have to > register. This is something like a normal forum. > > Is that possible? All I found is the sfDoctrineGuardPlugin plugin, but > all it says is that for creating useres I must use a task, and this is > not what I want: I want everyone to feel free to subscribe whenever > they want, without my confirmation. > > Than you in advance > Marco, Italy > > -- > If you want to report a vulnerability issue on symfony, please send it to > security at symfony-project.com > > You received this message because you are subscribed to the Google > Groups "symfony users" group. > To post to this group, send email to symfony-users@googlegroups.com > To unsubscribe from this group, send email to > symfony-users+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/symfony-users?hl=en > -- Have a nice day! Alecs Certified ScrumMaster There are no cannibals alive! I have ate the last one yesterday ... I am on web: http://www.alecslupu.ro/ I am on twitter: http://twitter.com/alecslupu I am on linkedIn: http://www.linkedin.com/in/alecslupu Tel: (+4)0722 621 280 -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups "symfony users" group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
