I finaly found what i'm looking for : The solution was the use of the
'method' option which let me choose the field i want to display from
the foreign table.
Thanks
public function configure()
{
$this->setWidgets(array(
'oid_cdp' => new sfWidgetFormDoctrineChoice(array('model'
=> $this->getRelatedModelName('CDP'),'method'
=>'getNameres','order_by' => array('nameres', 'asc'), 'add_empty' =>
true)),
On 16 sep, 18:26, ScherlOMatic <stefan.scherbich...@gmail.com> wrote:
> Hello!
>
> I think there is more than one solution for your problem.
>
> Try to overwrite the '_toString()' method in the model
> (TrackerManagerTable.class.php). Or create some own method and call it
> from whereever you want.
>
> Why are you implementing this logic in the filter class?
>
> BR
>
> On 16 Sep., 12:34, ziclo <lauren...@gmail.com> wrote:
>
> > Hello,
>
> > In my form filters i want to display a "select" widget (multi
> > choice). My problem is that the id appears but i want manager's name
> > instead (relation one to many). I also want to display another field,
> > manager's firstname. How can i do ?
>
> > Here is my formfilter class :
>
> > public function configure()
> > {
>
> > //Widgets
> > $this->setWidgets(array(
>
> > 'id_manager' => new sfWidgetFormDoctrineChoice(array('model'
> >
=> $this->getRelatedModelName('TrackerManager'), 'add_empty' =>
> > true)),
> > ));
>
> > //Validators
> > $this->setValidators(array(
>
> > 'id_manager' => new
> > sfValidatorDoctrineChoice(array('required' => false, 'model' =>
> > $this->getRelatedModelName('TrackerManager'), 'column' => 'id')),
>
> > ));
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
Groups "symfony users" group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
symfony-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/symfony-users?hl=en
