Comment #1 on issue 1620 by asmeurer: Allow derivatives of unknown functions evaluated at a point http://code.google.com/p/sympy/issues/detail?id=1620
Another way (that may or may not work), would be to use subs directly, like f(x).diff(x, 2).subs(x, 1). Right now it does: In [1]: f(x).diff(x).subs(x, 0) Out[1]: f(0) In [2]: f(x).diff(x, 2).subs(x, 0) Out[2]: f(0) which is wrong anyway. -- You received this message because you are listed in the owner or CC fields of this issue, or because you starred this issue. You may adjust your issue notification preferences at: http://code.google.com/hosting/settings --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to sympy-issues@googlegroups.com To unsubscribe from this group, send email to sympy-issues+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en -~----------~----~----~----~------~----~------~--~---
