Comment #4 on issue 1620 by asmeurer: Allow derivatives of unknown
functions evaluated at a point
http://code.google.com/p/sympy/issues/detail?id=1620
Great. When this gets fixed, I'll send in a patch implementing
initial/boundary conditions in dsolve(), as I would
like to use this for the syntax (i.e., dsolve(expr, func, ics={f(0):0,
diff(f(x). x).subs(x, 0):1}) to use the initial
conditions f(0)=0, f'(0)=1).
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