Status: Accepted Owner: asmeurer Labels: Type-Defect Priority-Medium Simplify
New issue 2327 by asmeurer: sqrt(I) should return sqrt(2)/2 + sqrt(2)/2*I by default
http://code.google.com/p/sympy/issues/detail?id=2327 In [31]: sqrt(I) Out[31]: 4 ⎽⎽⎽⎽ ╲╱ -1 In [32]: sqrt(I).expand(complex=True) Out[32]: ⎽⎽⎽ ⎽⎽⎽ ╲╱ 2 ⅈ⋅╲╱ 2 ───── + ─────── 2 2 I think the output of [31] should be the same as the output of [32]. -- You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to sympy-issues@googlegroups.com. To unsubscribe from this group, send email to sympy-issues+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en.
