Comment #4 on issue 2327 by smi...@gmail.com: sqrt(I) should return sqrt(2)/2 + sqrt(2)/2*I by default
http://code.google.com/p/sympy/issues/detail?id=2327
I could see trying to automatically remove the complex number from the denominator as we do with radicals so 1/(1+I) goes to 1/2 - I/2 the way 1/I goes to -I and 1/sqrt(2) goes to sqrt(2)/2...but I would leave sqrt(I) alone.
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