On Mon, Nov 10, 2008 at 10:46 PM, Brian Granger <[EMAIL PROTECTED]> wrote:
>
> Never mind, I figured this out myself:
>
> On Mon, Nov 10, 2008 at 1:15 PM, Brian Granger <[EMAIL PROTECTED]> wrote:
>> OK, sounds great.  Now a follow on....or two...
>>
>> * How can I get the non-commuting part of the Mul?  I see that
>> Mul.flatten knows about it, but I don't see how to get it back.
>
> Just do
>
> Mul.flatten(o.args) where o is my Mul instance
>
>> * I then need to take an expression, find all the instances of Mul in
>> the tree and replace those by something else, one by one.  Is there a
>> simple way of doing this?  the most common usage case that I will have
>> is a sum of terms;
>
> Use o.atoms(Mul) to get a set of all the Mul instances and then use
> o.subs(old, new) to rewrite them all.

Yes, that's actually also a solution -- you now know sympy more than I do. :)

Ondrej

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