Aaron S. Meurer a écrit :
>
> Interval(3, 4, endpoints='oc'), which would create (3, 4] ('oc' stands  
> for open-closed).

Hello here is a first try fopr working with sets. This code has been 
writing directly as I was thinking of what I neede. I think that it 
could be better. I'll work on unions of intervals : ythis would be 
simply a list of single intervals with additional methods so as to 
simplify a union. For the moment, only the intersection has been made. I 
hope that I didn't forget something.

Every kind of suggestion is welcome.

Christophe.

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#!/usr/bin/env python
#coding=utf-8


# Code writing by BAL Christophe
# Mail : projet...@club.fr

class Interval():
    def __init__(self, a, b, endpoints ='cc'):
        if endpoints not in ['cc', 'oc', 'co', 'oo']:
            raise Exception, 'Unkown endpoints of interval : "' + 
str(endpoints) + '"'

        self.endpoints = endpoints

        if a>b:
            self.min,self.max = b,a
            self.endpoints_min, self.endpoints_max = endpoints[1], endpoints[0]
        else:
            self.min = a
            self.max = b
            self.endpoints_min = endpoints[0]
            self.endpoints_max = endpoints[1]
    
    def __str__(self):
        if self.min == self.max:
            if self.endpoints == 'cc':
                return '{' + str(self.min) + '}'
            else:
                return 'Empty Set'

        if self.endpoints_min=='c':
            t = '['
        else:
            t =']'
        
        t+=str(self.min) + ';' + str(self.max)

        if self.endpoints_max=='c':
            t += ']'
        else:
            t +='['

        return t

    def intersection(self, otherInterval):
# The intersection is empty.
        if self.min == self.max or otherInterval.min == otherInterval.max:
            return Interval(0, 0, 'oo')
        
        maxOfMins = max(self.min, otherInterval.min)
        minOfMaxs = min(self.max, otherInterval.max)

        if maxOfMins > minOfMaxs:
            return Interval(0, 0, 'oo')

        if self.min == self.max or otherInterval.min == otherInterval.max:
            return Interval(0, 0, 'oo')

# The intersection could be a set with a single element.
        if minOfMaxs == maxOfMins:
            if self.max == minOfMaxs:
                if self.endpoints_max == 'o' or otherInterval.endpoints_min 
=='o':
                    return Interval(0, 0, 'oo')
                else:
                    return Interval(minOfMaxs, minOfMaxs)

            else:
                if self.endpoints_min == 'o' or otherInterval.endpoints_max 
=='o':
                    return Interval(0, 0, 'oo')
                else:
                    return Interval(minOfMaxs, minOfMaxs)

# Wath is the endpoints of the intersection ?
        answerendpoints_min = 'c'
        
        if self.min == maxOfMins :
            answerendpoints_min = self.endpoints_min
            
        if otherInterval.min == maxOfMins and answerendpoints_min == 'c':
            answerendpoints_min = otherInterval.endpoints_min
        
        answerendpoints_max = 'c'
        
        if self.max == minOfMaxs :
            answerendpoints_max = self.endpoints_max
            
        if otherInterval.max == minOfMaxs and answerendpoints_max == 'c':
            answerendpoints_max = otherInterval.endpoints_max
        
        return Interval(maxOfMins, minOfMaxs, 
answerendpoints_min+answerendpoints_max)


#########################
# SOME EXAMPLES TO TEST #
#########################

listEx = []

listEx.append("""I = Interval(-4, -2, 'oo')
J = Interval(3, 5, 'oc')""")
listEx.append("""I = Interval(-4, -2, 'oo')
J = Interval(-12, -7, 'oc')""")

listEx.append("""I = Interval(3, -4, 'oo')
J = Interval(3, 3, 'oc')""")
listEx.append("""I = Interval(3, -4, 'oo')
J = Interval(3, 5, 'oc')""")

listEx.append("""I = Interval(3, -4, 'co')
J = Interval(3, 5, 'co')""")
listEx.append("""I = Interval(3, 5, 'co')
J = Interval(-4, 3, 'cc')""")

listEx.append("""I = Interval(-4, 3, 'oo')
J = Interval(-4, 3, 'oc')""")
listEx.append("""I = Interval(-4, 3, 'cc')
J = Interval(-4, 3, 'co')""")

listEx.append("""I = Interval(-4, 3, 'cc')
J = Interval(-4, 5, 'co')""")
listEx.append("""I = Interval(-4, 3, 'oc')
J = Interval(-4, 5, 'co')""")
listEx.append("""I = Interval(-5, 3, 'cc')
J = Interval(-4, 3, 'co')""")
listEx.append("""I = Interval(-5, 3, 'cc')
J = Interval(-4, 3, 'cc')""")
listEx.append("""I = Interval(-5, 3, 'co')
J = Interval(-4, 3, 'cc')""")
listEx.append("""I = Interval(-5, 3, 'oc')
J = Interval(-4, 3, 'cc')""")
listEx.append("""I = Interval(-5, 3, 'oo')
J = Interval(-4, 3, 'cc')""")


###########################
# WRITING OF THE EXAMPLES #
###########################

#for i in range(len(examples)):
for i in range(len(listEx)):
    exec(listEx[i])
    for line in listEx[i].splitlines():
        print line

    I_inter_J = I.intersection(J)
    print '\tI : ' + str(I)
    print '\tJ : ' + str(J)
    print '\tI_inter_J : ' + str(I_inter_J)

    print '-'*30

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