On Nov 6, 9:13 am, "Aaron S. Meurer" <asmeu...@gmail.com> wrote:
> I think there is no need to run solve. The function will always be
> linear in dy/dx, because it is a linear operator, so the solution will
> always be -diff(eq, ind)/diff(eq, dep).
> Seehttp://en.wikipedia.org/wiki/Implicit_differentiation#Formula_for_two...
>
That's such a nice property--dazzlingly simple!
/c
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