Scott wrote: > My integral has several pieces like this: > > int^x1_x0 int ^t0_t1 (dot(del_a(t)).T* R *b ) dt dx > > del_a is 3*1, b is 3*1 and R is 3*3 rotation tensor( or a non > orthogonal velocity transformation tensor H) > > R,H and b are are constant over the interval of integration. > R=H inv(H.T) > > My goal is to perform symbolic manipulations, plug in basis functions > and do collections in del_a R b form while preserving the vector > orientations. > > With del_a linear (C1) in time the answer should be: (x1-x0)(del_a > (t1).T-del_a(t0).T)* R* b = scalar > At this time all the pieces are added together and collected wrt the > del terms yielding a nonlinear system. At this point the tensors are > populated. > > On Dec 1, 3:28 pm, Scott<scotta_2...@yahoo.com> wrote: > >> Is there a sympy function for making symbolic tensors? >> Basically I want to treat 3x3 rotation tensor symbol that is constant >> inside of an integral while preserving the tensor algebra (A*B .ne. >> B*A). The 3x3 rotain tensor is multiplied by a 3x1 position tenosr >> which is integrated. >> >> Is there a built in function for converting a 3*1 tensor to a skew >> antisymetric cross product matrix then back again? >> V/R >> >> Scott >> > -- > > You received this message because you are subscribed to the Google Groups > "sympy" group. > To post to this group, send email to sy...@googlegroups.com. > To unsubscribe from this group, send email to > sympy+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > > > > Where is the position (x) dependence in the intergrand?
-- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sy...@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
