Chris,

when I execute your code I get the error: TypeError: sympify() got an
unexpected keyword argument 'rational'.

I installed sympy using apt-get install python-sympy and synaptic
reports 0.6.7-1.1 as the installed version.

When I execute ?S I don't see any options for rational.
Call def: S(a, locals=None, convert_xor=True)

The same is true for nsimplify(2.3, rational=1)

from sympy import nsimplify
nsimplify(2.3, rational=1)

TypeError: nsimplify() got an unexpected keyword argument 'rational'

Again executing ?nsimplify mentions no rational param.
Definition: nsimplify(expr, constants=[], tolerance=None, full=False)

Any ideas?
Cathal

from sympy.geometry import *
from sympy import S

def rat(d):
   return S(str(d), rational=True)

p1 = Point(rat(-694310.42867240659), rat(7051910.5392115889))
TypeError: sympify() got an unexpected keyword argument 'rational'

p2 = Point(rat(-694286.161023414), rat(7051916.4164796043))
l=Line(p1,p2)
p = Point(rat(-694210.80222825997), rat(7051914.7562929001))

s = l.perpendicular_segment(p)
s.length

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