Hullo Sympy Group,
I'm wrapping some Sympy variables into a group via a class object. The
object is attached to another object, and from here, I'm able to collect
the name of the group (via *__setattr__*). Thus, I can have constructs
like this:
-----
*M.X = Var() # Var is the wrapper class that holds a group variables.
*
*M.X[1,2,'a'] = 1 # automatically create variable*
-----
That automatically creates the variable '*X[1,2,a]*' via the *
Var.__getitem__*. To get the name with commas, I have to do this within
the *__getitem__* function:
-----
*1. self.m_varsInUse += 1*
*2. vname = '%s[%d]' % ( self.m_name, self.m_varsInUse )*
*3. var = symbols( vname, **assumptions )*
*4. var.name = '%s(%s)' % (self.m_name, str(index).replace(' ', ''))*
-----
Lines 1 and 2 guarantee a new variable, so that Sympy doesn't returned a
cached copy of an already created variable, and line 4 puts in a name that
potentially has commas. What I'd like to be able to do is forgo lines one
and two, like something akin to this:
-----
*vname = '%s(%s)' % (self.m_name, str(index).replace(' ', ''))*
*var = symbols( vname, **assumptions )*
-----
This seems to return names like 'X[1', '2', and 'a]'. I'd hazard splitting
based on commas is correct behavior, but I'm wondering if there's something
I can pass to the constructor that says "No, the commas are part of the
name."
Thanks,
Kevin
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