On related note. Is this a but / missing feature?

In [69]: sympify(lambda x: x)
SympifyError: SympifyError: "could not parse u'<function <lambda> at
0x4a4bed8>'"


On 10 January 2012 17:34, krastanov.ste...@gmail.com <
krastanov.ste...@gmail.com> wrote:

> The problem of "python functions evaluate immediately sympy functions
> don't" is obvious when one tries to plot/lambdify something that contains
> both Expr and some numerical routine. Try to imagine a way to plot
> nsolve(..)*some_Expr for example.
>
> On 10 January 2012 17:30, krastanov.ste...@gmail.com <
> krastanov.ste...@gmail.com> wrote:
>
>> Or more likely it's better to use implemented_function that is imported
>> from utilities.lambdify?
>> It seems to me that implemented_function is quite important if one wants
>> for example to have complicated numerical routines accessible as sympy
>> expressions. In my opinion it's actually important enough to be mentioned
>> in the tutorial/pitfalls. Because defining a function to be used in sympy
>> is actually not as simple as defining a python function (python functions
>> evaluate immediately, sympy functions do not).
>>
>> Another question that I need help with is what is Lambda used for. Is
>> there something that Lambda does and implemented_function does not?
>>
>>
>> On 10 January 2012 16:39, krastanov.ste...@gmail.com <
>> krastanov.ste...@gmail.com> wrote:
>>
>>> How can I represent an unevaluated call to nsolve as a sympy expression?
>>> Is Lambda the best (and standard) solution?
>>>
>>> The expression I want to represent looks like nsolve(x-tanh(x-h),[x],0).
>>> The free symbol is h. It's in the context of plotting phase transition
>>> diagrams.
>>>
>>
>>
>

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