I found the usefull summation function, which seems to work well (examples from todays version from git)
In [30]: summation(1/k**2,(k,1,oo)) Out[30]: 2 π ── 6 In [31]: summation( (-1)**k * binomial(n,k), (k,0,n)) Out[31]: 0 But: In [32]: summation( binomial(n,k), (k,0,n)) Out[32]: n ____ ╲ ╲ ⎛n⎞ ╲ ⎜ ⎟ ╱ ⎝k⎠ ╱ ╱ ‾‾‾‾ k = 0 Which should be possible to do! (I think sage can do that one) Kjetil -- "If you want a picture of the future - imagine a boot stamping on the human face - forever." George Orwell (1984) -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sympy@googlegroups.com. To unsubscribe from this group, send email to sympy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
