Hi, > It's not exactly the best name, but the method you are looking for is > nth(). The arguments are powers of the generators. > > In [21]: Poly(3*x**3+2*x+12, gens=[x]).nth(3) > Out[21]: 3 > > In [22]: Poly(2*3*4*x*y*exp(8) + 23*x, gens=[x,y]).nth(0, 1) > Out[22]: 0 > > In [23]: Poly(2*3*4*x*y*exp(8) + 23*x, gens=[x,y]).nth(1, 0) > Out[23]: 23
Ok, thanks. I'd have to find the powers, probably with the monoms function after converting my monomials to true polynomials too. Maybe wo should change the name? -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To post to this group, send email to sympy@googlegroups.com. Visit this group at http://groups.google.com/group/sympy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
