This is the answer, according to Wolfram Alpha
http://www.wolframalpha.com/input/?i=sum(sin(n*x)%2C+(n%2C+1%2C+N))&dataset=.
I guess the value at 0 has to be taken as a limit.
The Sum means that SymPy can't do it. SymPy doesn't have the algorithms to
compute this summation. Its summation algorithms are not particularly
strong. There are classes of summations that it can compute, and this
apparently isn't in one of them.
Aaron Meurer
On Sun, Jan 4, 2015 at 3:43 AM, Gaurav Dhingra <axyd0...@gmail.com> wrote:
> I came across something which i think should have been solved by sympy:
>
> > from sympy import
>
>
> *> x, y, z = symbols('x y z')> n, N = symbols('n N', integer=True)>
> summation(sin(n*x), (n, 1, N))
> Sum(sin(n*x), (n, 1, N)) # so it returns the expression as it is
>
>
>
>
> I expected the answer to be a *piece-wise* function, what's the catch in
> this ?
>
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