Hello.
Maybe, it could be useful to have a abssimplify method that will try to
simplify abs expressions.
Christophe BAL
Le 11 févr. 2015 11:54, "Arnaud Usciati" <rait...@gmail.com> a écrit :
>
> Hi,
>
> I found another error limit :
> If x = symbols('x', positive=True), limit(tan(abs(x))/acosh(x), x, pi/2,
'-') returns oo --> OK
> If x = symbols('x', real=True), limit(tan(abs(x))/acosh(x), x, pi/2, '-')
returns oo*sign(1/Subs(Derivative(re(_x), _x), (_x,), (0,))) !!
>
> I guess the first result is correct because sympy can evaluate abs(x) to
x for x positive, but for x real it can't simplify the function and
calculate the limit !
>
> Le samedi 7 février 2015 05:08:05 UTC+1, Ondřej Čertík a écrit :
>>
>> The limits will have to be debugged, essentially we just need to go
>> step by step and see which routine returns the wrong answer.
>>
>> Ondrej
>>
>> On Fri, Feb 6, 2015 at 8:11 PM, Aaron Meurer <asme...@gmail.com> wrote:
>> > Be sure to test against SymPy master. As Ondrej pointed out, this used
to
>> > work, but it got broken.
>> >
>> > Aaron Meurer
>> >
>> > On Fri, Feb 6, 2015 at 5:55 PM, Douglas Lohmann <dloh...@gmail.com>
wrote:
>> >>
>> >> In my test it's not a bug. You can explain better?
>> >>
>> >> In [9]: limit(abs(log(x)), x, 0, '+')
>> >> Out[9]: oo
>> >>
>> >> It was already reported the bug to the bug list?
>> >>
>> >> Em sábado, 31 de janeiro de 2015 13:33:40 UTC-2, Arnaud Usciati
escreveu:
>> >>>
>> >>> Hello,
>> >>>
>> >>> limit(abs(log(x)), x, 0, '+') should return +oo, but it returns
>> >>> -oo*sign(log(_w)) !!!
>> >>>
>> >>>
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