Hmm, the last column of your martrix is zero, so it cannot be inverted because its determiant (e.det()) is zero. So how would Mathematica be able to calculate an inverse?
gerardo...@gmail.com schrieb am Dienstag, 11. Januar 2022 um 13:30:02 UTC+1: > Sure, sorry about the image, I was unaware of how easy is to generate > python code with the print methods > > from sympy import Symbol, Matrix,I > gamma_c = Symbol('gamma_c') > n_c = Symbol('n_c') > gamma_h = Symbol('gamma_h') > n_h = Symbol('n_h') > epsilon_c = Symbol('epsilon_c') > g = Symbol('g') > epsilon_h = Symbol('epsilon_h') > e = Matrix([[-gamma_c*(n_c + 1) - gamma_h*(n_h + 1), 0, 0, 0, 0, > gamma_c*n_c, 0, 0, 0, 0, gamma_h*n_h, 0, 0, 0, 0, 0], [0, -I*epsilon_c - > gamma_c*n_c/2 - gamma_c*(n_c + 1)/2 - gamma_h*(n_h + 1), I*g, 0, 0, 0, 0, > 0, 0, 0, 0, gamma_h*n_h, 0, 0, 0, 0], [0, I*g, -I*epsilon_h - gamma_c*(n_c > + 1) - gamma_h*n_h/2 - gamma_h*(n_h + 1)/2, 0, 0, 0, 0, gamma_c*n_c, 0, 0, > 0, 0, 0, 0, 0, 0], [0, 0, 0, -gamma_c*n_c/2 - gamma_c*(n_c + 1)/2 - > gamma_h*n_h/2 - gamma_h*(n_h + 1)/2 - I*(epsilon_c + epsilon_h), 0, 0, 0, > 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, -gamma_c*n_c/2 - gamma_c*(n_c + > 1)/2 - gamma_h*(n_h + 1) - I*(epsilon_h - (epsilon_c + epsilon_h)), 0, 0, > 0, -I*g, 0, 0, 0, 0, 0, gamma_h*n_h, 0], [gamma_c*(n_c + 1) - gamma_h*n_h, > 0, 0, 0, 0, -gamma_c*n_c - gamma_h*n_h - gamma_h*(n_h + 1), I*g, 0, 0, > -I*g, -gamma_h*n_h, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, I*g, -gamma_c*n_c/2 - > gamma_c*(n_c + 1)/2 - gamma_h*n_h/2 - gamma_h*(n_h + 1)/2 - I*(-epsilon_c + > epsilon_h), 0, 0, 0, -I*g, 0, 0, 0, 0, 0], [0, 0, gamma_c*(n_c + 1), 0, 0, > 0, 0, -I*epsilon_h - gamma_c*n_c - gamma_h*n_h/2 - gamma_h*(n_h + 1)/2, 0, > 0, 0, -I*g, 0, 0, 0, 0], [0, 0, 0, 0, -I*g, 0, 0, 0, -gamma_c*(n_c + 1) - > gamma_h*n_h/2 - gamma_h*(n_h + 1)/2 - I*(epsilon_c - (epsilon_c + > epsilon_h)), 0, 0, 0, 0, gamma_c*n_c, 0, 0], [0, 0, 0, 0, 0, -I*g, 0, 0, 0, > -gamma_c*n_c/2 - gamma_c*(n_c + 1)/2 - gamma_h*n_h/2 - gamma_h*(n_h + 1)/2 > - I*(epsilon_c - epsilon_h), I*g, 0, 0, 0, 0, 0], [-gamma_c*n_c + > gamma_h*(n_h + 1), 0, 0, 0, 0, -gamma_c*n_c, -I*g, 0, 0, I*g, -gamma_c*n_c > - gamma_c*(n_c + 1) - gamma_h*n_h, 0, 0, 0, 0, 0], [0, gamma_h*(n_h + 1), > 0, 0, 0, 0, 0, -I*g, 0, 0, 0, -I*epsilon_c - gamma_c*n_c/2 - gamma_c*(n_c + > 1)/2 - gamma_h*n_h, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, > -gamma_c*n_c/2 - gamma_c*(n_c + 1)/2 - gamma_h*n_h/2 - gamma_h*(n_h + 1)/2 > + I*(epsilon_c + epsilon_h), 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, > gamma_c*(n_c + 1), 0, 0, 0, 0, I*epsilon_h - gamma_c*n_c - gamma_h*n_h/2 - > gamma_h*(n_h + 1)/2, I*g, 0], [0, 0, 0, 0, gamma_h*(n_h + 1), 0, 0, 0, 0, > 0, 0, 0, 0, I*g, I*epsilon_c - gamma_c*n_c/2 - gamma_c*(n_c + 1)/2 - > gamma_h*n_h, 0], [gamma_c*n_c + gamma_h*n_h, 0, 0, 0, 0, gamma_c*n_c + > gamma_h*n_h + gamma_h*(n_h + 1), 0, 0, 0, 0, gamma_c*n_c + gamma_c*(n_c + > 1) + gamma_h*n_h, 0, 0, 0, 0, 0]]) > > However, I care more about how to speed up matrix inversion in general, as > it was terribly fast in Mathematica and it never finished in sympy. I guess > there is a more efficient way than using > > e.inv() > El martes, 11 de enero de 2022 a las 3:21:33 UTC+1, Oscar escribió: > >> On Monday, 10 January 2022 at 15:51:49 UTC gerardo...@gmail.com wrote: >> >>> Hi, >>> >>> So I was working in some problem and I had to switch to mathematica due >>> to the time the inverse of a matrix was taking, in mathematica it was >>> solved in less than a second while the computation in sympy has been >>> running for a day and hasn't finished. >>> >>> Is there anyway to speed up matrix inversion in sympy? >>> >>> Given that it is so much faster in mathematica is there any interest in >>> implementing some method (maybe theirs) that yields the inverse of a matrix >>> faster? if so I'd like to do it maybe someone could give me some pointers >>> to get me started >>> >>> The matrix is 15*15 and attached as an image, but any example of how to >>> speed things up will do. Thanks a lot! >>> >> >> The image is not a useful way to share this. Can you show simple code to >> make this matrix? >> >> (i.e. just the code to make the symbols and then something like the >> repr() of the matrix but make sure it's fully runnable code without any >> missing bits) >> >> -- >> Oscar >> > -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/37a7e8b1-1523-463b-bdfa-26ca1e73a247n%40googlegroups.com.