> i don't understand the rationale behind your code: [...] > To me, the fadeOut value is set using a function which calls fadeIn.
http://en.wikipedia.org/wiki/Callback_(computer_science) We're passing in a function as an argument*. This function will be executed once (IOW deferred until) the fadeOut animation has completed. Since that's an asynchronous operation, we can't just provide a sequence of statements like "fadeOut(); fadeIn();". Because of its non-sequential nature, asynchronous programming can seem a little weird at first (and, with JavaScript, often requires a good understanding of closures and variable scope), but it's not so bad once you wrap your head around it. -- F. * FWIW, it might be less confusing this way: var callback = function(ev) { jQuery(this).fadeIn(); }; jQuery(place).fadeOut(callback); -- You received this message because you are subscribed to the Google Groups "TiddlyWiki" group. To post to this group, send email to tiddlyw...@googlegroups.com. To unsubscribe from this group, send email to tiddlywiki+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/tiddlywiki?hl=en.
