Thanks FND, very helpful best wishes
Alex On 20 December 2010 12:56, FND <[email protected]> wrote: > > i don't understand the rationale behind your code: [...] > > To me, the fadeOut value is set using a function which calls fadeIn. > > http://en.wikipedia.org/wiki/Callback_(computer_science) > > We're passing in a function as an argument*. This function will be > executed once (IOW deferred until) the fadeOut animation has completed. > Since that's an asynchronous operation, we can't just provide a sequence > of statements like "fadeOut(); fadeIn();". > > Because of its non-sequential nature, asynchronous programming can seem > a little weird at first (and, with JavaScript, often requires a good > understanding of closures and variable scope), but it's not so bad once > you wrap your head around it. > > > -- F. > > > * FWIW, it might be less confusing this way: > var callback = function(ev) { > jQuery(this).fadeIn(); > }; > jQuery(place).fadeOut(callback); > > -- > You received this message because you are subscribed to the Google Groups > "TiddlyWiki" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<tiddlywiki%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/tiddlywiki?hl=en. > > -- You received this message because you are subscribed to the Google Groups "TiddlyWiki" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/tiddlywiki?hl=en.
